Answer the following 2 questions CORRECTLY I will know if this is wrong. I WILL REPORT ANY INCORRECT ANSWERS!
Criteria for getting brainliest and not getting reported:
- Show work
- Explain if you can't show work why this answer is correct.
- And make sure not to post random answers points are taken away when you are reported so don't think about answering it if you want only just want points to move up.

1. Solve and identify the solution. 6(6x - 2) + 8(1 - 5x) = 2x
A) [tex]x = \frac{2}{3}[/tex]
B) Infinite many solutions
C) No solution
D) x = [tex]-\frac{2}{3}[/tex]

2. Solve and identify the solution. 2(x + 5) = 2x + 5
A) x = 2
B) x = -2
C) no solution
D) infinite solution

1. [tex]\mathrm{Expand\:}6\left(6x-2\right)+8\left(1-5x\right)\\-4x-4=2x\\\mathrm{Add\:}4\mathrm{\:to\:both\:sides}\\-4x-4+4=2x+4\\Simplify\\-4x=2x+4\\\mathrm{Subtract\:}2x\mathrm{\:from\:both\:sides}\\-4x-2x=2x+4-2x\\\mathrm{Simplify}: -6x=4\\\mathrm{Divide\:both\:sides\:by\:}-6: \frac{-6x}{-6}=\frac{4}{-6}\\Simplify\\x=-\frac{2}{3}[/tex]

2. [tex]\mathrm{Expand\:}2\left(x+5\right)\\2x+10=2x+5\\\mathrm{Subtract\:}10\mathrm{\:from\:both\:sides}\\2x+10-10=2x+5-10\\Simplify\\2x=2x-5\\\mathrm{Subtract\:}2x\mathrm{\:from\:both\:sides}\\2x-2x=2x-5-2x\\Simplify\\0=-5\\The\:sides\:are\:not\:equal\\No\:Solution[/tex]