Respuesta :
The quadratic formula is (-b±√(b²-4ac))÷2a
The quadratic formula sounded out is negative b plus or minus the square root of b squared minus four a times c all divided by two a.
Answer:
Step-by-step explanation:
For a quadratic equation [tex]ax^2+bx+c=0[/tex]
we can complete the squares
Divide by a to get
[tex]x^2+\frac{bx}{a} +\frac{c}{a} =0[/tex]
Complete the square as
[tex](x+\frac{b}{2a} )^2 -\frac{b^2}{4a^2} -+\frac{c}{a} =0\\(x+\frac{b}{2a} )^2=\frac{b^2}{4a^2} --\frac{c}{a}=\frac{b^2-4ac}{2a}[/tex]
Take square root
[tex](x+\frac{b}{2a} =\sqrt{\frac{b^2-4ac}{2a} }\\x=\frac{=b+/-\sqrt{b^2-4ac} }{2a}[/tex]
