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iiMGii
Let's solve this problem step-by-step.

STEP-BY-STEP SOLUTION:

To begin with, let's establish that ( x ) can equal to any number from 0 to 9.

Meaning, that ( x ) is equal to one of the following: 0, 1, 2, 3, 4, 5, 6, 7, 8 or 9.

Now that we know which values ( x ) can equal to, we will simply substitute each of the numbers as potential values of ( x ) into the six-digit number and divide it by 27 to see if it is a multiple of 27.

If X = 0

= 63X904 / 27

= 630904 / 27

= Not a whole number

Therefore, X is not equal to 0.

If X = 1

= 63X904 / 27

= 631904 / 27

= Not a whole number

Therefore, X is not equal to 1.

If X = 2

= 63X904 / 27

= 632904 / 27

= Not a whole number

Therefore, X is not equal to 2.

If X = 3

= 63X904 / 27

= 633904 / 27

= Not a whole number

Therefore, X is not equal to 3.

If X = 4

= 63X904 / 27

= 634904 / 27

= Not a whole number

Therefore, X is not equal to 4.

If X = 5

= 63X904 / 27

= 635904 / 27

= 23552

ANSWER:

Therefore, the answer is:

X = 23, 552

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Desidemona

Answer:

X=5

Step-by-step explanation:

First, let's factorize 27.

27: 1x27

     3x9

     9x3(Same as 3x9)    

Anything divided by 1 equals that number, so 1 will not help reduce the options for 1 and we already know that 63X904 is divisible by 27. The only two factors left are 3 and 9, so we now know that 63X904 is divisible by 3 and 9.

This question is not so hard if you know your divisibility rules.

The divisibility rule for 3 is that when you add all the digits of the number together, the sum is divisible by 3.

The divisibility rule for 9 is the same as the rule for 3, except the sum is supposed to be divisible by 9.

6+3+9+4=22

The important part is that 63X904 has to be divisible by 3 and 9. The only number that fits those requirements is 27, of course.

27-22=5. Therefore, X=5.

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