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If a stress of 1.05 × 107 n/m2 is applied to his ligament, how much will it stretch? the young\'s modulus for the acl is 1.10 × 108 n/m2.

Respuesta :

As we know that

[tex]Young's\: Modulus = \frac{stress}{strain}[/tex]

here we know that

[tex]Young's Modulus = 1.10 \times 10^8[/tex]

[tex]stress = 1.05 \times 10^7[/tex]

now by the above formula we will have

[tex]1.10 \times 10^8 = \frac{1.05 \times 10^7}{strain}[/tex]

[tex]strain = \frac{1.05 \times 10^7}{1.10 \times 10^8}[/tex]

[tex]strain = 0.095[/tex]


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