Respuesta :

Hussam7
There might be something wrong with the answer if 2/x not correct.
tramserran

Answer: B) [tex]\frac{2}{x}[/tex]

Step-by-step explanation:

  [tex]\frac{x^{2}+8x}{3x^{2}+3x} - \frac{x^{2}+2x-6}{3x^{2}+3x}[/tex]

= [tex]\frac{x^{2}+8x- x^{2}-2x+6}{3x^{2}+3x} [/tex]

= [tex]\frac{6x+6}{3x^{2}+3x}[/tex]

= [tex]\frac{6(x+1)}{3x(x+1)}[/tex]

= [tex]\frac{6}{3x}[/tex]

= [tex]\frac{2}{x}[/tex]

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