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The volume of a sphere increases with the cube of its radius. If the radius of a sphere increases from 2 cm to 6 cm. by what factor does its volume increase

Respuesta :

If im not wrong

Answer

volume increases with a  factor of 27

Explanation;

The volume of a sphere is given by the formula

V = 4/3 πr³

When the radius is 2 cm the volume will be;

V = 4/3 π (2)³

 = 32/3 π

When the increases to 6 cm the volume will be ;

V = 4/3 π (6)³

= 864/3 π

Hence, the volume increases by a factor;

(864/3 π) ÷ (32/3 π)

= 27


Thus, the volume increases with a factor 27


The volume of the sphere is calculated by the formula [tex]\dfrac{4}{3}\pi r^3[/tex], where r is radius of the sphere.

Given that, the radius of the sphere increased from 2 cm to 6 cm, such that:

V = [tex]\dfrac{4}{3}\pi r^3[/tex]

where, radius = 2 cm

V = [tex]\dfrac{4}{3}\pi \;(2)^3[/tex]

V = [tex]\dfrac{32}{3}\pi[/tex]

Now, when the radius increased from 2 cm to 6 cm, such that:

[tex]\rm V = \dfrac{4}{3}\pi r^3\\\\\rm V = \dfrac{4}{3}\pi (6)^3\\\\\rm V = \dfrac{864}{3}\pi[/tex]

Now, the volume will increase by the factor:

[tex]\rm V = \dfrac{864}{3}\pi \;\div\; \dfrac{32}{3}\pi\\\\\rm V = 27[/tex]

Thus, the volume of the sphere will increase by the factor 27.

To know more about volume, refer to the following link:

https://brainly.com/question/16924154