Respuesta :
Answer:
option-A
(5)
Step-by-step explanation:
we are given
[tex]5x^3-135[/tex]
Firstly, we can factor out 5
[tex]5x^3-5\times 27[/tex]
[tex]5(x^3-27)[/tex]
[tex]5(x^3-3^3)[/tex]
now, we can use formula of factor
[tex]a^3-b^3=(a-b)(a^2+ab+b^2)[/tex]
we can compare
a=x , b=3
now, we can plug this into formula
[tex]5(x^3-3^3)=5(x-3)(x^2+3\times x+3^2)[/tex]
[tex]5(x^3-3^3)=5(x-3)(x^2+3x+9)[/tex]
so, we get
[tex]5x^3-135=5(x-3)(x^2+3x+9)[/tex]
so, only factor 5 matches
Answer:
The correct answer option is A) 5.
Explanation:
We are given the following expression and we are to factorize it:
[tex]5x^3-135[/tex]
If we take the common term out of this, then we are left with:
[tex]5(x^3-27)[/tex]
Now the term [tex](x^3-27)[/tex] can also be written in the form of [tex]x^3-y^3[/tex] as:
[tex]x^3-3^3[/tex]
Next, we will factorize it applying the difference of cubes formula [tex]x^3-y^3=(x-y)(x^2+xy+y^2)[/tex] to get:
[tex]x^3-3^2= \left(x-3\right)\left(x^2+3x+3^2\right)[/tex]
[tex]=\left(x-3\right)\left(x^2+3x+3^2\right)[/tex]
[tex]=\left(x-3\right)\left(x^2+3x+9\right)[/tex]
Adding the common term back to it to get:
[tex]5\left(x-3\right)\left(x^2+3x+9\right)[/tex]
Therefore, from the given answer options we can see that the option A) 5 is the factor of the given expression 5x^3 - 135.