Answer : The volume of carbon dioxide will be, 5.6122 L
Solution : Given,
Moles of LiOH = 0.5 moles
Molar mass of carbon dioxide = 44 g/mole
Density of carbon dioxide = 0.00196 g/ml
First we have to calculate the mass of carbon dioxide.
The balanced reaction will be,
[tex]2LiOH+CO_2\rightarrow Li_2CO_3+H_2O[/tex]
From the reaction we conclude that
As, 2 moles of LiOH absorbs 44 grams of carbon dioxide
So, 0.5 moles of LiOH absorbs [tex]\frac{0.5moles}{2moles}\times 44g=11[/tex] grams of carbon dioxide
Mass of carbon dioxide = 11 g
Density of carbon dioxide = 0.00196 g/ml
Now we have to calculate the volume of carbon dioxide.
[tex]Density=\frac{Mass}{volume}[/tex]
[tex]0.00196g/ml=\frac{11g}{volume}[/tex]
Volume of carbon dioxide = 5612.24 ml = 5.6122 L (1 L = 1000 ml)
Therefore, the volume of carbon dioxide will be, 5.6122 L
