savage285668
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The potential energy of a charge q moving from A to B at point A is 5.4 × 10-10 joules and at point B is 2.3 × 10-10 joules. The charge is 2.5 × 10-15 coulombs. What potential difference does the particle undergo?

A.
2.3 × 103 volts
B.
2.5 × 104 volts
C.
5.4 × 104 volts
D.
7.0 × 104 volts
E.
1.2 × 105 volts

Respuesta :

Potential difference is defined as change in potential energy per unit charge

we can write it as

[tex]V_2 - V_1 = \frac{U_2 - U_1}{q}[/tex]

given that

[tex]U_A = 5.4 \times 10^{-10} J[/tex]

[tex]U_B = 2.3 \times 10^{-10} J[/tex]

[tex]q = 2.5 \times 10^{-15} C[/tex]

now we will have

[tex]V_2 - V_1 = \frac{5.4 \times 10^{-10} - 2.3 \times 10^{-10}}{2.5 \times 10^{-15}}[/tex]

[tex]V_2 - V_1 = 1.2 \times 10^5 Volts[/tex]

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