Respuesta :
Answer:
The first four terms of the above sequence are 1, 6, 11, 16.
Step-by-step explanation:
A sequence is defined by the function f(n)=f(n-1)+5.
Where n represents the number of the term for n>1
First Put n = 2
f(2)=f(2-1)+5.
= f (1) + 5
= -4 + 5
= 1
Second Put n = 3
f(3)=f(3-1)+5.
= f (2) + 5
= 1 + 5
= 6
Third Put n = 4
f(4)=f(4-1)+5.
= f (3) + 5
= 6+ 5
= 11
Second Put n = 5
f(5)=f(5-1)+5.
= f (4) + 5
= 11 + 5
= 16
Therefore the first four terms of the above sequence are 1, 6, 11, 16.
Answer: The first four terms are -4, 1, 6 and 11.
Step-by-step explanation: The function which defines the given sequence is
f(n) = f(n-1) + 5, where 'n' is the number of terms for n>1 and the first term is
f(1) = -4.
So, second term = f(2) = f(1) + 5 = -4+5 = 1.
Third term = f(3) = f(2) + 5 = 1+5 = 6.
Fourth term = f(4) = f(3) + 5 = 6+5 = 11.
Thus, the first four terms of the sequence are -4, 1, 6 and 11.
