In the following lever system, what is the counter-clockwise torque?
6 Nm
300 Nm
1,200 Nm
1,800 Nm

B) 300Nm
I know its 300Nm because I had this on my usatestprep quiz
The answer is: 300 N.m
Torque is equal to the product between the applied force and the distance from the pivot (where the lever is supported), we are given a lever system with 2 applied forces at different distances from the pivot, and we are asked to find what is the counter-clockwise torque, so:
The counter-clockwise torque is located at the left end of the lever, so:
[tex]Torque=Force*Distance=300N*1m=300N.m[/tex]
So, the counter-clockwise torque is equal to 300 N.m.
Also, we can calculate the clockwise torque:
[tex]Torque=Force*Distance=200N*6m=1200N.m[/tex]
Have a nice day!