Answer:
Step-by-step explanation:
Given a circle is inscribed in a rhombus with sides of length 4 cm. If the two acute angles in the rhombus each measure 60 degrees. we have to find the radius of circle.
In the rhombus the acute angles is of 30° and also the line OE is perpendicular to side AB and also bisects the side AB gives AE= 2 cm
In ΔAOE , ∠OAE=30°
AE= 2 cm
⇒[tex]tan30=\frac{OE}{AE}=\frac{1}{\sqrt{3}}[/tex]
⇒ [tex]OE= \frac{2}{\sqrt{3}}=\frac{2}{3}\sqrt{3}[/tex]
