Answer:
Step-by-step explanation:
Given two sides of a triangle 2x – 4 and 7x – 2 units.
Difference of two sides of a triangle is less than third side.
Let us find the difference of 7x – 2 and 2x – 4, we get
7x-2 - (2x-4) = 7x -2 -2x +4
= 5x + 2.
Third side should be less then 5x+2, so 5x+2 can't be third side.
Sum of two sides is greater than third side.
Adding given sides of triangle, we get
7x-2 +2x-4 = 9x - 6.
Third side should be greater than 9x-6. So, 9x-6 can't be third side.
Now, if we add 3x and 2x-4, we get
3x+2x-4 = 5x-4, which is less than 9x - 6.
So, 3x can't be third side.
Therefore, correct option is :
The lengths of the sides of a triangle must all be a positive number of units. For this reason, since 2x – 4 and 7x – 2 must both be positive, x must be greater than 2, and when x is greater than 2, 7x – 2 is always greater than 2x – 4. Thus, the third side of the triangle must be less than (7x – 2) + (2x – 4) units long and greater than (7x – 2) – (2x – 4) units long. In other words, it must be less than 9x – 6 units long and greater than 5x + 2 units long. Therefore, a possible length for the third side of the triangle is 6x units.
