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A 5 N force is applied to a 3 kg ball to change its velocity from 9 m/s to 3 m/s. What is the impulse on the ball ?

Respuesta :

natasha2502
So, first the formula of Impulse is
I = force * time
We have force but no time.
Then, find time.
Next find acceleration,
F = mass * acceleration
5 = 3 * a
1.67 m/s^2
Next find time,
Acceleration = change in velocity / time
Change in velocity is velocity final - velocity initial
1.67 = 3 - 9 / time
Time = 3.6 s (round to 2 s.f.)
Lastly,
Impulse = force * time
Impulse = 5 * 3.6
Impulse is 18 Ns
Cricetus

The impulse on the ball will be "18 kg.m/s".

According to the question,

Force,

  • F = 5 N

Mass,

  • m = 3 kg

Velocity,

  • v₁ = 9 m/s and v₂ = 3 m/s

As we know,

→ [tex]I = \Delta P[/tex]

or,

→ [tex]I = mv_2 -mv_1[/tex]

By substituting the given values, we get

→    [tex]= 3(3)-3(9)[/tex]

→    [tex]=9-27[/tex]

→    [tex]= -18 \ kg.m/s[/tex] (represents opposite direction)

Thus the above approach is right.

Learn more about Impulse here:

https://brainly.com/question/20404537

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