Answer : [tex]F=2808\times 10^{-11}\ N[/tex]
Explanation :
It is given that,
Charge, [tex]q=0.650\ \mu C=0.65\times 10^{-6}\ C[/tex]
Velocity of Aircraft, [tex]v=540\ m/s[/tex] (in west)
Magnetic field, [tex]B=8 \times 10^{-5}\ T[/tex] ( in north )
Using the relation as :
[tex]F=q(v\times B)[/tex]
Magnetic force is ,
[tex]F=0.65\times 10^{-6}\ C\times 540\ m/s\times 8 \times 10^{-5}\ T[/tex]
[tex]F=2808\times 10^{-11}\ N[/tex]
Using Right hand thumb rule, the direction of force is in the plane perpendicular to the velocity and the magnetic field i.e. [tex]-\hat{k}[/tex].