Answer:
1.55 mol
Step-by-step explanation:
We can use the Ideal Gas Law to solve this problem.
pV = nRT Divide both sides by RT
n = (pV)/(RT)
Data:
p = 1.40 atm
V = 27.5 L
R = 0.082 06 L·atm·K⁻¹mol⁻¹
T = 302 K
Calculations:
n = (1.40 × 27.5)/(0.082 06 × 302)
= 1.55 mol
1.55 mol is in the sample of gas if a volume of 27.5 L at 302 K and 1.40 atm
A mole is defined as 6.02214076 × [tex]10^{23}[/tex]of some chemical unit, be it atoms, molecules, ions, or others. The mole is a convenient unit to use because of the great number of atoms, molecules, or others in any substance.
Step-by-step explanation:
We can use the Ideal Gas Law to solve this problem.
pV = nRT Divide both sides by RT
n = (pV)/(RT)
Data:
p = 1.40 atm
V = 27.5 L
R = 0.082 06 L·atm·K⁻¹mol⁻¹
T = 302 K
Calculations:
n = (1.40 × 27.5)/(0.082 06 × 302)
1.55 mol.
Hence, 1.55 mol is in the sample of gas.
Learn more about moles here:
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