Answer : The final energy of the system if the initial energy was 2000 J is, 3500 J
Solution :
(1) The equation used is,
[tex]\Delta U=q+w\\\\U_{final}-U_{initial}=q+w[/tex]
where,
[tex]U_{final}[/tex] = final internal energy
[tex]U_{initial}[/tex] = initial internal energy
q = heat energy
w = work done
(2) The known variables are, q, w and [tex]U_{initial}[/tex]
initial internal energy = [tex]U_{initial}[/tex] = 2000 J
heat energy = q = 1000 J
work done = w = 500 J
(3) Now plug the numbers into the equation, we get
[tex]U_{final}-(2000J)=(1000J)+(500J)[/tex]
(4) By solving the terms, we get
[tex]U_{final}-(2000J)=(1000J)+(500J)[/tex]
[tex]U_{final}-(2000J)=1500J[/tex]
[tex]U_{final}=2000J+1500J[/tex]
[tex]U_{final}=3500J[/tex]
(5) Therefore, the final energy of the system if the initial energy was 2000 J is, 3500 J