answer
Height at which kiwi reach=1.2m
Solution
In this question we have given
mass of apple, [tex]m_{a} =.6kg[/tex]
mass of kiwi,[tex]m_{a} =.25kg[/tex]
height from which apple is dropped,[tex]H_{a} =.5m[/tex]
Let the height at which kiwi reached is [tex]H_{k}[/tex]
here,
We will apply law of conservation of energy
it means,
potential energy of kiwi= potential energy of apple
[tex]m_{k}\times g\times H_{k}= m_{a}\times g\times H_{a}[/tex]......(1)
here g is gravitational acceleration
put values of [tex]m_{k} , g, H_{k}, m_{a}[/tex] and [tex]H_{a}[/tex] in equation 1
[tex].25kg\times H_{k}=.6kg\times .5m\\H_{k}=\frac{.3kg\times m}{.25kg} \\H_{k}=1.2m[/tex]
therefore, Height at which kiwi reach=1.2m
