A gas at constant pressure occupies 0.400 L at 50.0°C. What volume will it have at 300.°C? If you could show work that would really be appreciated.

Respuesta :

This can be solved using the Combined Gas Law. The formula for that is

[tex]\frac{P_{1} V_{1} }{T_{1} } = \frac{P_{2} V_{2} }{T_{2} }[/tex]

Let's go ahead and fill in our known values. Since pressure remains the same, it doesn't matter what number we use, so let's assume 1 atm on both sides. For temperature, remember to convert it to Kelvin first (K = C + 273).

[tex]\frac{(1 atm) (0.400 L)}{(323 K)} = \frac{(1 atm) (x L)}{(573 K)}[/tex]

Go ahead and simplify both sides.

0.001238 =  [tex]\frac{(x L)}{(573 K)}[/tex]

Multiply both sides by 573.

0.7095 = x L

So, at 300° C, your gas will occupy 0.7095 L.