For this case we have that the slope of a line is given by:
[tex]m = \frac {y2-y1} {x2-x1}[/tex]
We have the following points:
[tex](x1, y1) = (- 2,19)\\(x2, y2) = (5, -9)[/tex]
Substituting:
[tex]m = \frac {-9-19} {5 - (- 2)}\\m = \frac {-28} {5 + 2}\\m = \frac {-28} {7}\\m = -4[/tex]
Thus, the slope-intercept form equation is given by:
[tex]y = -4x + b[/tex]
We substitute any of the points to find the cut point with the y axis.
[tex]-9 = -4 (5) + b\\-9 = -20 + b\\b = -9 + 20\\b = 11[/tex]
So, we have:
[tex]y = -4x + 11[/tex]
Answer:
Option B
