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two boats are anchored in the harbor, separated my a horizontal distance of 14m. The boats boo up and down as waves enter the harbor. When one boat is at its highest point, the other is at its lowest point and there are no crests between them. each boat makes exactly 5 complete up-and-down cycles every 15.0 s. the vertical distance between a boats highest and lowest position is 2.4m.
find the wavelength,
frequency, period, amplitude and speed

Respuesta :

Given:

Horizontal distance between two boats = x = 14 m

One boat is at trough, the other is at crest.

As there is no crests between them meaning the boat are next to each other.

Wavelength is the distance between two consecutive crests/troughs = w

The distance between a crest and a trough next to it = w/2

Complete cycles = c = 5

Time taken for c cycles = t = 15 s

Vertical distance between two boats = y = 2.4 m

To find:

wavelength = w = 2x = 28 m

Amplitude =  A = Displacement from mean to extreme position = y/2 = 1.2 m

Time period for one cycle = T = t/c = 15/5 = 3 s/cycle

frequency = 1/T = 1/3 = 0.33 hertz

speed = wavelength/Period = w/T = 28/3 = 9.33 m/s

The wavelength, frequency, period, amplitude, and speed will be 28 m,1.2 m, 3 s/cycle,0.33 hertz, and 9.33 m/s respectively.

What is wavelength?

The distance between two successive troughs or crests is known as the wavelength. The peak of the wave is the highest point, while the trough is the lowest.

The given data In the problem is;

[tex]\rm \lambda[/tex] is the Wavelength

The distance between a crest and a trough next to it = w/2

c is the  Complete cycles = 5

t is the time taken for c cycles = 15 s

y is the vertical distance between two boats = 2.4 m

The wavelength of the wave is found as;

[tex]\frac{\lambda}{2} =x \\\\ \lambda = 2x \\\\ \lambda = 2 \times 14 \\\\ \lambda = 28 m[/tex]

The amplitude of the wave is found as;

[tex]\rm A = \frac{y}{2} \\\\ A=1.2 \ m[/tex]

The time for the one cycle is the ratio of total time to the number of cycles.

[tex]\rm T = \frac{t}{c} \\\\ \rm T = \frac{15}{5} \\\\\rm T = 3 \ sec/cycle[/tex]

The speed of the wave is found as the ratio of the wavelength and the time period;

[tex]\rm v =\frac{\lambda}{T} \\\\ \rm v =\frac{28}{3} \\\\ \rm v =9.33 \ m/sec[/tex]

Hence the wavelength, frequency, period, amplitude, and speed will be 28 m,1.2 m, 3 s/cycle,0.33 hertz, and 9.33 m/s respectively.

To learn more about the wavelength refer to the link;

brainly.com/question/7143261