2x+8y=4 What is the slope of a line parallel to this line? What is the slope of a line perpendicular to this line?

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TNSKermit TNSKermit · Answer 1 · 2019-03-07T14:25:18+01:00

Let's solve for x.

2x+8y=4

Step 1: Add -8y to both sides.

2x+8y+−8y=4+−8y

2x=−8y+4

Step 2: Divide both sides by 2.

2x/2

=

−8y+4/2

=−4y+2

Answer:

x=−4y+2

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jimrgrant1 jimrgrant1 · Answer 2 · 2019-03-07T14:38:54+01:00

Answer:

see explanation

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Rearrange 2x + 8y = 4 into this form

Subtract 2x from both sides

8y = - 2x + 4 ( divide all terms by 8 )

y = - [tex]\frac{1}{4}[/tex] x + [tex]\frac{1}{2}[/tex] ← in slope- intercept form

with slope m = - [tex]\frac{1}{4}[/tex]

• Parallel lines have equal slopes, thus

slope of parallel line = - [tex]\frac{1}{4}[/tex]

Given a line with slope m then the slope of a line perpendicular to it is

[tex]m_{perpendicular}[/tex] = - [tex]\frac{1}{m}[/tex] = - [tex]\frac{1}{-\frac{1}{4} }[/tex] = 4