In circle O, AP = √10, PB = x and BC = 3. Find the value of x.

Answer:
The value of x is [tex]2\ units[/tex]
Step-by-step explanation:
we know that
Applying the tangent-secant theorem
[tex]AP^{2}=PB*PC[/tex]
substitute the values and solve for x
[tex]\sqrt{10}^{2}=x*(x+3)[/tex]
[tex]10=x^{2}+3x[/tex]
[tex]x^{2}+3x-10=0[/tex]
using a graphing tool
to solve the quadratic equation
The solution is [tex]x=2\ units[/tex]
see the attached figure