Answer:
3-√11
Step-by-step explanation:
If a polynomal function f(x) has roots 0, 4 and 3+√11, then 3-√11 must be also a root of f(x).
Probably, we are in front of a four degree polynomial. The first two roots were found, and then the last root was found using the quadratic formula, which states that for a polynomial of the time [tex]ax^{2} +bx + c = 0[/tex]. The roots are given by:
[tex]x1 = \frac{-b+\sqrt{b^{2}-4ac } }{2a}[/tex]
[tex]x2 = \frac{-b-\sqrt{b^{2}-4ac } }{2a}[/tex]
We have that one root is 3+√11, therefore the other one should be 3-√11.
