Respuesta :
Answer:
[tex]4.1\cdot 10^8 N[/tex]
Explanation:
First of all, we need to find the pressure exerted on the sphere, which is given by:
[tex]p=p_0 + \rho g h[/tex]
where
[tex]p_0 =1.01\cdot 10^5 Pa[/tex] is the atmospheric pressure
[tex]\rho = 1000 kg/m^3[/tex] is the water density
[tex]g=9.8 m/s^2[/tex] is the gravitational acceleration
[tex]h=11,000 m[/tex] is the depth
Substituting,
[tex]p=1.01\cdot 10^5 Pa + (1000 kg/m^3)(9.8 m/s^2)(11,000 m)=1.08\cdot 10^8 Pa[/tex]
The radius of the sphere is r = d/2= 1.1 m/2= 0.55 m
So the total area of the sphere is
[tex]A=4 \pi r^2 = 4 \pi (0.55 m)^2=3.8 m^2[/tex]
And so, the inward force exerted on it is
[tex]F=pA=(1.08\cdot 10^8 Pa)(3.8 m^2)=4.1\cdot 10^8 N[/tex]
The total inward force is about 4.1 × 10⁸ N
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Further explanation
Let's recall Hydrostatic Pressure formula as follows:
[tex]\boxed{ P = \rho g h}[/tex]
where:
P = hydrosatic pressure ( Pa )
ρ = density of fluid ( kg/m³ )
g = gravitational acceleration ( m/s² )
h = height of a column of liquid ( m )
Let us now tackle the problem!
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Given:
depth of the ocean's floor = h = 11 000 m
diameter pilot sphere = d = 1.1 m
atmospheric pressure = Po = 10⁵ Pa
Asked:
total inward force = F = ?
Solution:
[tex]F = P A[/tex]
[tex]F = ( P_o + \rho g h ) A[/tex]
[tex]F = ( P_o + \rho g h ) ( \pi d^2 )[/tex] → Area of Sphere = π d²
[tex]F = ( 10^5 + 1000 \times 9.8 \times 11000 ) ( \pi \times 1.1^2 )[/tex]
[tex]F \approx 4.1 \times 10^8 \texttt{ Newton}[/tex]
[tex]\texttt{ }[/tex]
Conclusion:
The total inward force is about 4.1 × 10⁸ N
[tex]\texttt{ }[/tex]
Learn more
- Buoyant Force : https://brainly.com/question/13922022
- Kinetic Energy : https://brainly.com/question/692781
- Volume of Gas : https://brainly.com/question/12893622
- Impulse : https://brainly.com/question/12855855
- Gravity : https://brainly.com/question/1724648
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Answer details
Grade: High School
Subject: Physics
Chapter: Pressure
