A 0.20 kg plastic cart and a 20 kg lead cart can roll without friction on a horizontal surface. Equal forces are used to push both carts forward for a time of 1 , starting from rest. After the force is removed at t = 1s is the momentum of the plastic cart greater than, less than, or equal to the momentum of the lead cart? Explain.

Respuesta :

Answer:

The have equal momentum

Explanation:

The change in momentum of each cart is equal to the impulse given to the cart:

[tex]\Delta v = I = F \Delta t[/tex]

where

F is the average force exerted on the cart

[tex]\Delta t[/tex] is the contact time

In this case, the force F applied to both carts is the same, and the contact time is the same for both carts (1 s). Therefore, the change in momentum of the two carts is the same.

However, both carts at the beginning have a momentum of zero (because they start from rest): this means that their final momentum will be equal, since they gain the same amount of momentum [tex]\Delta p[/tex].