Answer:
240 H
Explanation:
The energy stored in an inductor is given by:
[tex]E=\frac{1}{2}LI^2[/tex]
where
L is the inductance of the inductor
I is the current
In this problem, we know:
[tex]I=300 A[/tex] is the current in the inductor
[tex]E=3.0 kWh = 3000 Wh[/tex] is the energy stored. We need to convert it into Joules:
[tex]E=3000 Wh=3000 Wh \cdot (3600 s/h)=1.08\cdot 10^7 J[/tex]
So, we can now solve the equation to find L, the inductance:
[tex]L=\frac{2E}{I^2}=\frac{2(1.08\cdot 10^7 J)}{(300 A)^2}=240 H[/tex]
