Answer:
[tex]\large\boxed{\dfrac{1}{3p+15}=\dfrac{1}{3(p+5)}}[/tex]
Step-by-step explanation:
"one over threep + 15":
[tex]\dfrac{1}{3p+15}=\dfrac{1}{(3)(p)+(3)(5)}=\dfrac{1}{(3)(p+5)}=\dfrac{1}{3(p+5)}[/tex]
Answer:
[tex]\frac{1}{3(p+5)}[/tex].
Step-by-step explanation:
We are asked to find equivalent expression to the expression [tex]\frac{1}{3p+15}[/tex].
We can see that terms in denominator of our given rational expression share a common factor. The common factor is 3.
Let us factor out 3 from denominator:
[tex]\frac{1}{3*p+3*5}[/tex]
[tex]\frac{1}{3(p+5)}[/tex]
Therefore, the expression [tex]\frac{1}{3(p+5)}[/tex] is equivalent to our given expression.
