Answer:
x = -5
y = -2
Step-by-step explanation:
[tex]\left\{\begin{array}{ccc}3x+4y=-23&(1)\\x=3y+1&(2)\end{array}\right\\\\\text{Substitute (2) to (1):}\\\\3(3y+1)+4y=-23\qquad\text{use the distributive property}\\\\(3)(3y)+(3)(1)+4y=-23\\\\9y+3+4y=-23\qquad\text{subtract 3 from both sides}\\\\13y=-26\qquad\text{divide both sides by 13}\\\\\boxed{y=-2}\\\\\text{Put the value of }\ y\ \text{to (2)}:\\\\x=3(-2)+1\\\\x=-6+1\\\\\boxed{x=-5}[/tex]
