Two disks with the same rotational inertia i are spinning about the same frictionless shaft, with the same angular speed ω, but with opposite angular velocities ~ω and −~ω. what is the total rotational kinetic energy kr of this system of two disks? 1. 1 2 i ω 2 2. zero 3. none of these

Respuesta :

Answer:

3. none of these

Explanation:

The rotational kinetic energy of an object is given by:

[tex]K=\frac{1}{2}I \omega^2[/tex]

where

I is the moment of inertia

[tex]\omega[/tex] is the angular speed

In this problem, we have two objects rotating, so the total rotational kinetic energy will be the sum of the rotational energies of each object.

For disk 1:

[tex]K_1 = \frac{1}{2}I (\omega)^2 = \frac{1}{2}I\omega^2[/tex]

For disk 2:

[tex]K_2 = \frac{1}{2}I(-\omega)^2 = \frac{1}{2}I\omega^2[/tex]

so the total energy is

[tex]K=K_1 + K_2 = \frac{1}{2}I\omega^2 + \frac{1}{2}I\omega^2 = I\omega^2[/tex]

So, none of the options is correct.

The total rotational kinetic energy of this system is : ( C ) none of these

Ker =  Iw²

Determine the Total rotational kinetic energy

Given that the two disks have the same rotational inertia and the same angular speed but opposite angular velocities

w and -w

Total rotational kinetic energy ( Kr )

K.Er = K₁ + K₂

     = [tex]\frac{1}{2} * Iw^2 + \frac{1}{2} * I (-w)^2[/tex]

     = [tex]Iw^2[/tex]

Hence the total rotational kinetic energy of the system is : Iw²

Learn more about rotational kinetic energy : https://brainly.com/question/15076457