Answer:
100.2 kg
Explanation:
The period of vibration of a spring-mass system is given by
[tex]T=2\pi \sqrt{\frac{m}{k}}[/tex]
where
T is the period
m is the mass
k is the spring constant
In this problem, we know
T = 1.419 s is the period
k = 1962 N/m is the spring constant
Re-arranging the equation, we can find the mass:
[tex]m=k(\frac{T}{2\pi})^2=(1962 N/m)(\frac{1.419 s}{2\pi})^2=100.2 kg[/tex]
