Answer:
Part 1) The value of x is [tex]2\sqrt{7}\ in[/tex]
Part 2) The value of y is [tex]\sqrt{21}\ in[/tex]
Step-by-step explanation:
Part 1
Find the value of x
Applying Pythagoras Theorem
[tex]8^{2}=x^{2} +6^{2}[/tex]
[tex]x^{2}=8^{2}-6^{2}[/tex]
[tex]x^{2}=28[/tex]
[tex]x=2\sqrt{7}\ in[/tex]
Part 2
Find the value of y
Applying Pythagoras Theorem
[tex]7^{2}=x^{2} +y^{2}[/tex]
substitute the value of x
[tex]7^{2}=28 +y^{2}[/tex]
[tex]y^{2}=7^{2}-28[/tex]
[tex]y^{2}=21[/tex]
[tex]y=\sqrt{21}\ in[/tex]