Identify the vertex of y = -1 (x-4)^2 +9 and tell whether it’s a minimum or maximum
please and thanks!

Answer:
maximum at (4, 9)
Step-by-step explanation:
The equation of a parabola in vertex form is
y = a(x - h)² + k
where (h, k) are the coordinates of the vertex and a is a multiplier
y = - 1(x - 4)² + 9 is in this form
with vertex = (4, 9)
• If a > 1 then vertex is a minimum
• If a < 0 then vertex is a maximum
here a = - 1 , hence vertex (4, 9) is a maximum