Answer:
Pr(z<0.05) = 0.5199
Step-by-step explanation:
We are required to determine the region under a standard normal curve less than z = 0.05. The value 0.05 is a z-score. The area of this region is equivalent to the following probability;
Pr(z<0.05)
In a standard normal curve, this is the region to the left of 0.05. Using the standard normal tables, this cumulative probability is equal to;
Pr(z<0.05) = 0.5199