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Select the correct answer
A group of 8 friends (5 girls and 3 boys) plans to watch a movie, but they have only 5 tickets. How many different combinations of 5 friends could
possibly receive the tickets?
•
A.13
B.40
C.56
D.64

Respuesta :

alinakincsem

Answer:

The correct answer option is C. 56.

Step-by-step explanation:

We are given that a group of 8 friends (5 girls and 3 boys) plans to watch a movie, but they have only 5 tickets.

We are to find the number of combinations these 5 friends could

possibly receive the tickets.

Here, we will use the concept of combination as the order of the friends is not specific.

[tex]5C5+ (5C4 * 3C1) + (5C3*3C2) + (5C2*3C3)[/tex]

[tex]=1+5*3 + 10*3 +10*1 = 1+15+30+10=[/tex] 56

Answer:

Answer is C.

Step-by-step explanation:

The general formula for calculating combinations is:

[tex]\frac{n!}{k!(n-k)!}[/tex]

Where n is the total number of options and k is the number of options in the combination.

In this case, sub in the numbers given in the question:

[tex]\frac{8!}{5!(8-5)!}[/tex]

[tex]=\frac{8\times 7 \times 6 }{3 \times 2}[/tex]

[tex]=8 \times 7[/tex]

[tex]=56[/tex]

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