If point E(5, h) is on the line that contains A(0, 1) and B(−2, −1), what is the value of h?

a)-1
b)0
c) 1
d) 6

Please Help !!!!!

Respuesta :

First calculate the change in y over the change in x:

by - ay -1 - 1 -2
———— = ——— = —— = 1
bx - ax -2 - 0 -2


The slope is 1:

Second set up the equation in y = mx + b form (m is your slope!) ...

y = (1)x + b

... and plug in either point you have used (A or B)

A(0,1)

1 = (1)(0) + b
1 = b

Now you have your equation: y = 1x + 1

Your final step is to plug in point C to solve for your missing variable:

y = (1)(5) + 1
y = 6

the value of H therefore is 6

The value of h on the line is 6

How to determine the value of h?

The points are given as:

E(5, h), A(0, 1) and B(−2, −1)

Calculate the slope using:

[tex]m = \frac{y_2 -y_1}{x_2 -x_1}[/tex]

So, we have:

[tex]\frac{1-h}{0-5}= \frac{1 + 1}{0 + 2}[/tex]

Evaluate the sum and difference

[tex]\frac{1-h}{-5}= \frac{2}{2}[/tex]

Evaluate the quotient

[tex]\frac{1-h}{-5}= 1[/tex]

Cross multiply

1 - h = -5

Solve for h

h = 1 + 5

Evaluate

h = 6

Hence, the value of h on the line is 6

Read more about linear equations at:

https://brainly.com/question/14323743

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