Respuesta :
First calculate the change in y over the change in x:
by - ay -1 - 1 -2
———— = ——— = —— = 1
bx - ax -2 - 0 -2
The slope is 1:
Second set up the equation in y = mx + b form (m is your slope!) ...
y = (1)x + b
... and plug in either point you have used (A or B)
A(0,1)
1 = (1)(0) + b
1 = b
Now you have your equation: y = 1x + 1
Your final step is to plug in point C to solve for your missing variable:
y = (1)(5) + 1
y = 6
the value of H therefore is 6
by - ay -1 - 1 -2
———— = ——— = —— = 1
bx - ax -2 - 0 -2
The slope is 1:
Second set up the equation in y = mx + b form (m is your slope!) ...
y = (1)x + b
... and plug in either point you have used (A or B)
A(0,1)
1 = (1)(0) + b
1 = b
Now you have your equation: y = 1x + 1
Your final step is to plug in point C to solve for your missing variable:
y = (1)(5) + 1
y = 6
the value of H therefore is 6
The value of h on the line is 6
How to determine the value of h?
The points are given as:
E(5, h), A(0, 1) and B(−2, −1)
Calculate the slope using:
[tex]m = \frac{y_2 -y_1}{x_2 -x_1}[/tex]
So, we have:
[tex]\frac{1-h}{0-5}= \frac{1 + 1}{0 + 2}[/tex]
Evaluate the sum and difference
[tex]\frac{1-h}{-5}= \frac{2}{2}[/tex]
Evaluate the quotient
[tex]\frac{1-h}{-5}= 1[/tex]
Cross multiply
1 - h = -5
Solve for h
h = 1 + 5
Evaluate
h = 6
Hence, the value of h on the line is 6
Read more about linear equations at:
https://brainly.com/question/14323743
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