On a given school day, the probability that Nick oversleeps is 48% and the probability he has a pop quiz
is 25%. Assuming these two events are independent, what is the probability that Nick oversleeps and has
pop quiz on the same day?

Respuesta :

Answer:

0.12

Step-by-step explanation:

Independent events are when probability of one event happening doesn't affect the probability of the other event happening.

Also,

In probability "AND" means "multiplication" and "OR" means "addition".

The question asks for probability that Nick oversleeps "AND" has pop quiz. So we need to multiply the individual probabilities (since independent, they have no affect on each other).

P(Nick oversleeps) = 0.48

P(pop quiz) = 0.25

Thus,

P(Nick oversleeps AND pop quiz) = 0.48 * 0.25 = 0.12

Using the probability of independent events, it is found that there is a 0.12 = 12% probability that Nick oversleeps and has pop quiz on the same day.

What is a probability?

A probability is given by the number of desired outcomes divided by the number of total outcomes.

When two events are independent, to find the probability of both happening, we multiply the probability of each.

In this problem, for the two independent events, the probabilities are:

P(A) = 0.48, P(B) = 0.25.

Hence:

[tex]P(A \cap B) = 0.48 \times 0.25 = 0.12[/tex]

0.12 = 12% probability that Nick oversleeps and has pop quiz on the same day.

More can be learned about probabilities at https://brainly.com/question/14398287