AC is a diameter, so
[tex](6x+5)^\circ+(5x+3)^\circ+(8x+1)^\circ=180^\circ[/tex]
[tex]\implies19x+9=180[/tex]
[tex]\implies19x=171[/tex]
[tex]\implies x=9[/tex]
BD is also a diameter, which makes angles AQB and CQD vertical pairs, hence
[tex]m\angle AQB=m\angle CQD=73^\circ[/tex]
Then
TRUE: [tex]m\angle EQD=(5\cdot9+3)^\circ=48^\circ[/tex]
TRUE: [tex]m\widehat{CE}=(8\cdot9+1)^\circ+(5\cdot9+3)^\circ=121^\circ[/tex]
FALSE: [tex]m\angle CQB=180^\circ+73^\circ=253^\circ[/tex]
FALSE: [tex]m\widehat{DCA}=180^\circ+73^\circ=253^\circ[/tex]
