For this case we must indicate an expression equivalent to:
[tex]\sqrt {\frac {2x ^ 5} {18}}[/tex]
We rewrite 18 as 2 * 9:
[tex]\sqrt {\frac {2x ^ 5} {2 * 9}} =[/tex]
We simplify common factors:
[tex]\sqrt {\frac {x ^ 5} {9}} =[/tex]
We rewrite:
[tex]x ^ 5 = x ^ 4 * x = (x ^ 2) ^ 2 * x\\9 = 3 ^ 2[/tex]
So, we have:
[tex]\sqrt {\frac {(x ^ 2) ^ 2 * x} {3 ^ 2}} =\\\sqrt {(\frac {x ^ 2} {3}) ^ 2 * x} =[/tex]
We get the terms of the radical "
[tex]\frac {x ^ 2} {3} \sqrt {x}[/tex]
Answer:
[tex]\frac {x ^ 2} {3} \sqrt {x}[/tex]
