Answer:
probability that their second child will have hemophilia= 1/2
Explanation:
Here, the woman had hemophilic mother (XhXh) making the woman carrier for the disease. Genotype of the woman =XhX
Genotype of hemophilic man = XhY
As per attached punnet square, out of total four children, one son and one daughter would be affected. One daughter would be normal but carrier. The other son would be normal.
Total probability of getting their second child affected with hemophilia = 1/4 daughter + 1/4 son = 1/2 (50%).
