Respuesta :
Answer:
2.5 x 10^-8 C
Explanation:
Diameter = 6 cm, radius = 3 cm = 0.03 m, d = 2 mm = 2 x 10^-3 m
E = 1 x 10^6 N/C, q = ?
q = C V
As we know that, V = E x d and C = ∈0 A / d
q = ∈0 x A x E x d / d
q = ∈0 x A x E
q = 8.854 x 10^-12 x 3.14 x 0.03 x 0.03 x 1 x 10^6
q = 2.5 x 10^-8 C
Electric field exerts a force on all charged particles. The charge on the electrode is 2.505 x 10⁻⁸ C.
What is an electric field?
An electric field can be thought to be a physical field that surrounds all the charged particles and exerts a force on all of them.
Given to us
Plate dimensions diameter, d = 6 cm
Area of the plate, A = πr² = π(0.03)² = 0.00283 m²
Distance between the two plates, d = 2 mm = 0.002 m
Electric field strength, E = 1.0 x 10⁶ N/C
We know that electric field inside a parallel plate capacitor is given as,
[tex]E = \dfrac{Q}{A\epsilon_0}[/tex]
Substitute the value,
[tex]1 \times 10^6 = \dfrac{Q}{0.00283 \times 8.854 \times 10^{-12}}[/tex]
Q = 2.505 x 10⁻⁸ C
Hence, the charge on the electrode is 2.505 x 10⁻⁸ C.
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