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Hey there!:
The number of students in the sample who have experienced math anxiety is a binomial distribution
Bin (n , p) where n = 10 and p = 0.2
The mean of a binomial distribution is np = 2
The variance is np (1- p) = 1.6 so the standard deviation is √ 1.6 = 1.265
mean=2; standard deviation= 1.265
Hope this helps!
The standard deviation of the of the number of students with anxiety in the sample which is the square root of the variance is 1.265
Probability of those who have experienced anxiety :
- P(anxiety) ; P = 20% = 0.2
- Number of samples, n = 10
The standard deviation can be defined thus :
- Standard deviation = √Variance
- Variance = [np(1 - p)]
- Variance = [(10 × 0.2 × (1 - 0.2)] = 1.6
- Standard deviation = √1.6
- Standard deviation = 1.265
Therefore, the standard deviation of the number of sampled students with anxiety is 1.265
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