Find the equation of the horizontal line that passes through the point (-5,6) using the point slope formula

Answer:
So first blank=6
Second blank=0
Third blank=-5
Fourth blank=6
Step-by-step explanation:
It is a horizontal line so the equation is just going to be
[tex]y=\text{ whatever y-coordinate they gave you in that one point}[/tex].
So it will be [tex]y=6[/tex]
We are going to do the point-slope form too as I requested.
Point-slope form is [tex]y-y_1=m(x-x_1)[/tex].
We have m=0 since you said the slope was 0 and since it said your have a horizontal line (which means the slope slope or m is 0).
You also that it contains the point [tex](-5,6)=(x_1,y_1)[/tex].
So our line in point-slope form is [tex]y-6=0(x-(-5))[/tex].