Answer:
A probe charge
Explanation:
As we know that electric field intensity is the force experienced by the probe charge which is placed in the electric field region
Here we can say it as
[tex]E = \frac{F}{q}[/tex]
so here that probe charge should be very small so that it will not disturb the electric field in the space.
If the probe charge is of large magnitude then the field will get disturbed and the intensity which is to be measured is different from its actual value.
Also the sign of the probe charge is taken to be positive.
so correct answer here will be
A probe charge
