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Two long, parallel wires are separated by a distance of 2.2 cm. The force per unit length that each wire exerts on the other is 3.6 × 10^-5 N/m, and the wires repel each other. The current in one wire is 0.52 A. What is the magnitude of the current in the second wire? (Give your answer in decimal using "A" (Ampere) as unit)

Respuesta :

Answer:

[tex]i_2 = 7.6 A[/tex]

Explanation:

As we know that the force per unit length of two parallel current carrying wires is given as

[tex]F = \frac{\mu_o i_1 i_2}{2\pi d}[/tex]

here we know that

[tex]F = 3.6 \times 10^{-5} N/m[/tex]

[tex]i_1 = 0.52 A[/tex]

d = 2.2 cm

now from above equation we have

[tex]3.6 \times 10^{-5} = \frac{4\pi \times 10^{-7} (0.52)(i_2)}{2\pi (0.022)}[/tex]

[tex]3.6 \times 10^{-5} = 4.73 \times 10^{-6} i_2[/tex]

[tex]i_2 = 7.6 A[/tex]