Answer : The new pressure is, 0.534 atm
Solution :
Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.
The combined gas equation is,
[tex]\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}[/tex]
where,
[tex]P_1[/tex] = initial pressure of gas = 1.00 atm
[tex]P_2[/tex] = final pressure of gas = ?
[tex]V_1[/tex] = initial volume of gas = 250 ml
[tex]V_2[/tex] = final volume of gas = 500 ml
[tex]T_1[/tex] = initial temperature of gas = [tex]20^oC=273+20=293K[/tex]
[tex]T_2[/tex] = final temperature of gas = [tex]40^oC=273+40=313K[/tex]
Now put all the given values in the above equation, we get the final pressure of gas.
[tex]\frac{1atm\times 250ml}{293K}=\frac{P_2\times 500ml}{313K}[/tex]
[tex]P_2=0.534atm[/tex]
Therefore, the new pressure is, 0.534 atm
