For this case we have the following expression:
[tex]\frac {1} {3} -2x-4y ^ 2[/tex]
We must evaluate the expression when:
[tex]x = 3\\y = -1[/tex]
Substituting we have:
[tex]\frac {1} {3} -2 (6) -4 (-1) ^ 2 =\\\frac {1} {3} -12-4 (1) =\\\frac {1} {3} -12-4 =[/tex]
Equal signs are added and the same sign is placed.
[tex]\frac {1} {3} -16 =[/tex]
Different signs are subtracted and the major sign is placed.
[tex]- \frac {47} {3}[/tex]
Answer:
[tex]- \frac {47} {3}[/tex]
