Answer : 0.0129
Step-by-step explanation:
Given : Based on FAA estimates the average age of the fleets of the 10 largest U.S. commercial passenger carriers is [tex]\mu=13.4[/tex] years and standard deviation is [tex]\sigma=1.7[/tex] years.
Sample size : [tex]n=40[/tex]
Let X be the random variable that represents the age of fleets.
We assume that the ages of the fleets of the 10 largest U.S. commercial passenger carriers are normally distributed.
For z-score,
[tex]z=\dfrac{x-\mu}{\dfrac{\sigma}{\sqrt{n}}}[/tex]
For x=14
[tex]z=\dfrac{14-13.4}{\dfrac{1.7}{\sqrt{40}}}\approx2.23[/tex]
By using the standard normal distribution table , the probability that the average age of these 40 airplanes is at least 14 years old will be :-
[tex]P(x\geq 14)=P(z\geq2.23)\\\\=1-P(z<2.23)\\\\1- 0.9871262=0.0128738\approx0.0129[/tex]
Hence, the required probability = 0.0129