Answer:
$83,320
Step-by-step explanation:
The formula to apply here is;
[tex]A=P(1+\frac{r}{n} )^{nt}[/tex]
where;
A=Amount at the end
P=the amount to invest/principal
r=rate of interest as a decimal
n=number of compoundings in a year
t=time in years
Given that;
A=$400,000
P=?
r=8%=0.08
n=2
t=20
Substitute values in equation
[tex]A=P(1+\frac{r}{n} )^{nt} \\\\\\400,000=P(1+\frac{0.08}{2} )^{2*20} \\\\\\400,000=P(1+0.04)^{40} \\\\\\\\400,000=P(1.04)^{40} \\\\\\400,000=P(4.80102062794)\\\\\\\\\frac{400,000}{4.80102062794} =\frac{4.80102062794P}{4.80102062794} \\\\\\83315.617=P\\\\[/tex]
P=$83,320 (to the nearest dollar)