Answer:
The right option is (d) 1.3 m/s^2
Explanation:
From the mass of the lunar module and the force printed by the engines I can obtain the acceleration that they produce:
F= m × a ⇒ a= (30000 kg × (m/s^{2}) ) / (10000kg) = 3 (m/s^{2})
This acceleration has an upward direction, and the gravitational acceleration of the moon has a downward direction, opposite to the first, so they are subtracted and the resulting acceleration will be:
Amoon= 1.6249 (m/s^{2})
Atotal= 3 (m/s^{2}) - 1.6249 (m/s^{2}) = 1.3751 (m/s^{2})